4x^2+25x-250=0

Solution for 4x^2+25x-250=0 equation:

4x^2+25x-250=0

a = 4; b = 25; c = -250;
Δ = b2-4ac
Δ = 252-4·4·(-250)
Δ = 4625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4625}=\sqrt{25*185}=\sqrt{25}*\sqrt{185}=5\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{185}}{2*4}=\frac{-25-5\sqrt{185}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{185}}{2*4}=\frac{-25+5\sqrt{185}}{8}
$